What is the domain of (2x+10)/(x^2-4x-5) ?

The domain of (2x+10)/(x^2-4x-5) is x 5

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domain of (2x+10)/(x^2-4x-5)

domain

\frac{2 x + 10}{x ^{2} - 4 x - 5}

x < - 1 or - 1 < x < 5 or x > 5

Interval Notation

(- \infty, - 1) \cup (- 1, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = 5, x = - 1

The function domain

x < - 1 or - 1 < x < 5 or x > 5

f (x) = \frac{2 x ^{2} + 2}{x + 2}

R (x) = (\frac{( x + 2 )}{( x + 5 )})

y = x^{4} - 4 x^{3} + 314 x^{2} - 79 x + 2

f (x) = \frac{1}{2 + 3}

y = \frac{3 x}{8 - x}

What is the domain of (2x+10)/(x^2-4x-5) ?
The domain of (2x+10)/(x^2-4x-5) is x<-1\lor-1<x<5\lor x>5