What is the domain of sqrt(16-x^2)-sqrt(x+1) ?

The domain of sqrt(16-x^2)-sqrt(x+1) is -1<= x<= 4

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domain of sqrt(16-x^2)-sqrt(x+1)

domain

16 - x^{2} - x + 1

- 1 \leq x \leq 4

Interval Notation

[- 1, 4]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 4

The function domain

- 1 \leq x \leq 4

f (x) = 5 - x - x^{2} - 4

3 x^{3} - 9 x + 1

3 cos (4 x)

f (x) = x^{4} - 18 x^{2}

f (x) = x^{3} - 3 x^{2} - 13 x + 15

What is the domain of sqrt(16-x^2)-sqrt(x+1) ?
The domain of sqrt(16-x^2)-sqrt(x+1) is -1<= x<= 4