What is the domain of f(x)=ln(sqrt(x^2-1))+2 ?

The domain of f(x)=ln(sqrt(x^2-1))+2 is x 1

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domain of f(x)=ln(sqrt(x^2-1))+2

domain

f (x) = ln (x^{2} - 1) + 2

x < - 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (1, \infty)

Solution steps

Find positive values for logs:

x < - 1 or x > 1

The function domain

x < - 1 or x > 1

f (x) = \frac{x + 3}{x ^{2} + 4 x - 5}

f (x) = \frac{x - 5}{x - 4 x}

f (x) = - x^{2} - 4 x - 5

f (x) = \frac{x ^{2}}{x - 1} + ln (4 - ∣ 2 x + 1 ∣)

f (x) = - x^{2} - 4 x - 6

What is the domain of f(x)=ln(sqrt(x^2-1))+2 ?
The domain of f(x)=ln(sqrt(x^2-1))+2 is x<-1\lor x>1