What is the domain of f(t)=2-sqrt(9-t^2) ?

The domain of f(t)=2-sqrt(9-t^2) is -3<= t<= 3

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domain of f(t)=2-sqrt(9-t^2)

domain

f (t) = 2 - 9 - t^{2}

- 3 \leq t \leq 3

Interval Notation

[- 3, 3]

Solution steps

Find non-negative values for radicals:

- 3 \leq t \leq 3

The function domain

- 3 \leq t \leq 3

f (x) = 1100 - 10 x

ln (5 - x^{2})

x + 6 - x

2^{x + \frac{1}{x}}

x^{4} - 6 x^{3} + 4 x^{2} + 24 x - 32

What is the domain of f(t)=2-sqrt(9-t^2) ?
The domain of f(t)=2-sqrt(9-t^2) is -3<= t<= 3