What is the domain of f(x)=log_{10}(16-x^2)+1 ?

The domain of f(x)=log_{10}(16-x^2)+1 is -4<x<4

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domain of f(x)=log_{10}(16-x^2)+1

domain

f (x) = lo g_{10} (16 - x^{2}) + 1

- 4 < x < 4

Interval Notation

(- 4, 4)

Solution steps

Find positive values for logs:

- 4 < x < 4

The function domain

- 4 < x < 4

f (x) = 200 x - x^{2} - 4000

g (x) = x + 4 + 3

y = 2^{\frac{x}{2}}

f (x) = lo g_{2} (x^{2} - 2 x - 3)

What is the domain of f(x)=log_{10}(16-x^2)+1 ?
The domain of f(x)=log_{10}(16-x^2)+1 is -4<x<4