What is the domain of r(x)=(x^2-2x-8)/(x^2+4x) ?

The domain of r(x)=(x^2-2x-8)/(x^2+4x) is x 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of r(x)=(x^2-2x-8)/(x^2+4x)

domain

r (x) = \frac{x ^{2} - 2 x - 8}{x ^{2} + 4 x}

x < - 4 or - 4 < x < 0 or x > 0

Interval Notation

(- \infty, - 4) \cup (- 4, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 4

The function domain

x < - 4 or - 4 < x < 0 or x > 0

f (x) = x (x) = ln (4 - x)

(x - 1) (\frac{300}{x} - 2)

f (x) = - 5 x - 2 y = 1

x^{4} - 2 x^{2} - 3 x - 2

\frac{x + 5}{3 x - 24}

What is the domain of r(x)=(x^2-2x-8)/(x^2+4x) ?
The domain of r(x)=(x^2-2x-8)/(x^2+4x) is x<-4\lor-4<x<0\lor x>0