What is the domain of log_{10}(x^2-8x+12) ?

The domain of log_{10}(x^2-8x+12) is x 6

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domain of log_{10}(x^2-8x+12)

domain

lo g_{10} (x^{2} - 8 x + 12)

x < 2 or x > 6

Interval Notation

(- \infty, 2) \cup (6, \infty)

Solution steps

Find positive values for logs:

x < 2 or x > 6

The function domain

x < 2 or x > 6

b (t) = 5 t - 0.625 t^{2}

f (x) = \frac{x ^{2} + 1}{3}

f (x) = ln (t - 4)

f (x) = ∣ 4 x + 2 ∣

f (x) = \frac{( 2 x ^{2} + 2 )}{x ^{2} - 4}

What is the domain of log_{10}(x^2-8x+12) ?
The domain of log_{10}(x^2-8x+12) is x<2\lor x>6