What is the domain of g(x)=sqrt(-8x+48) ?

The domain of g(x)=sqrt(-8x+48) is x<= 6

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domain of g(x)=sqrt(-8x+48)

domain

g (x) = - 8 x + 48

x \leq 6

Interval Notation

(- \infty, 6]

Solution steps

Find non-negative values for radicals:

x \leq 6

The function domain

x \leq 6

f (x) = x - \frac{1}{2} (x + 1)^{2} - 2

\frac{( 8 x ^{2} + 12 x )}{( 3 x - 2 ) ^{2}}

f (x) = \frac{( x - 6 )}{x + 9}

f (x) = \frac{( - x ^{2} + 1 )}{( x ^{2} + 2 x - 3 )}

\frac{1}{11 ( \frac{1}{11 x - 1} ) - 1}

What is the domain of g(x)=sqrt(-8x+48) ?
The domain of g(x)=sqrt(-8x+48) is x<= 6