What is the domain of f(x)= 1/(ln(sqrt(x+2))) ?

The domain of f(x)= 1/(ln(sqrt(x+2))) is -2 -1

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domain of f(x)= 1/(ln(sqrt(x+2)))

domain

f (x) = \frac{1}{ln ( x + 2 )}

- 2 < x < - 1 or x > - 1

Interval Notation

(- 2, - 1) \cup (- 1, \infty)

Solution steps

Find positive values for logs:

x > - 2

Find undefined (singularity) points:

x = - 1

Combine real regions and undefined points for final function domain

- 2 < x < - 1 or x > - 1

f (x) = (x - 6)^{2} - 6

f (x) = \frac{7 + x}{2 x}

f (x) = 4 x - 1 + (- 5 x^{2} + 3)

f (x) = \frac{1}{4 x + 11}

f (x) = e^{0.5 x} + 100 e^{- 0.5 x}

What is the domain of f(x)= 1/(ln(sqrt(x+2))) ?
The domain of f(x)= 1/(ln(sqrt(x+2))) is -2<x<-1\lor x>-1