What is the domain of f(x)=tan^2(x) ?

The domain of f(x)=tan^2(x) is pin<= x< pi/2+pin\lor pi/2+pin<x<pi+pin

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domain of f(x)=tan^2(x)

domain

f (x) = tan^{2} (x)

πn \leq x < \frac{π}{2} + πn or \frac{π}{2} + πn < x < π + πn

Interval Notation

[πn, \frac{π}{2} + πn) \cup (\frac{π}{2} + πn, π + πn)

Solution steps

Take the denominator(s) of

tan^{2} (x)

and compare to zero:

x = \frac{π}{2} + πn

Periodicity of

tan^{2} (x) : π

Combine period:

πn \leq x < π + πn

and undefined points.

The domain is

πn \leq x < \frac{π}{2} + πn or \frac{π}{2} + πn < x < π + πn

f (x) = 7 sin (x)

\frac{3 x}{4} - \frac{15}{4}

f (y) = - x - 3

f (x) = \frac{( x + 3 )}{x - 1}

- 2 - (- 2)^{3}

What is the domain of f(x)=tan^2(x) ?
The domain of f(x)=tan^2(x) is pin<= x< pi/2+pin\lor pi/2+pin<x<pi+pin