What is the domain of f(x)= 3/(x^2-36)+sqrt(x-2) ?

The domain of f(x)= 3/(x^2-36)+sqrt(x-2) is 2 6

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domain of f(x)= 3/(x^2-36)+sqrt(x-2)

domain

f (x) = \frac{3}{x ^{2} - 36} + x - 2

2 \leq x < 6 or x > 6

Interval Notation

[2, 6) \cup (6, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 6, x = - 6

Combine real regions and undefined points for final function domain

2 \leq x < 6 or x > 6

\frac{\frac{x}{x - 3}}{( \frac{x}{x - 3} ) - 3}

f (x) = ln (x^{2} + 3 x - 18)

- 3 x^{3} + 10 x^{2} - 13 x + 11

\frac{2 x}{5 x - 9}

6 - ∣ x ∣

What is the domain of f(x)= 3/(x^2-36)+sqrt(x-2) ?
The domain of f(x)= 3/(x^2-36)+sqrt(x-2) is 2<= x<6\lor x>6