What is the domain of f(x)=sqrt(90-x^2+x) ?

The domain of f(x)=sqrt(90-x^2+x) is -9<= x<= 10

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domain of f(x)=sqrt(90-x^2+x)

domain

f (x) = 90 - x^{2} + x

- 9 \leq x \leq 10

Interval Notation

[- 9, 10]

Solution steps

Find non-negative values for radicals:

- 9 \leq x \leq 10

The function domain

- 9 \leq x \leq 10

\frac{x + 6}{x ^{2}}

ln (x) 5 - 3 lo g_{3} (1 - 2 x)

f (x) = 7^{x} - 3

- \frac{9 - 8 x}{7 x + 8}

What is the domain of f(x)=sqrt(90-x^2+x) ?
The domain of f(x)=sqrt(90-x^2+x) is -9<= x<= 10