What is the domain of y=sqrt(5(x-5)+40) ?

The domain of y=sqrt(5(x-5)+40) is x>=-3

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domain of y=sqrt(5(x-5)+40)

domain

y = 5 (x - 5) + 40

x \geq - 3

Interval Notation

[- 3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 3

The function domain

x \geq - 3

f (x) = - \frac{4}{3} x^{2} + 42 x

x^{3} + 3 x^{2}

y = 7 + ln (x - 9)

f (x) = \frac{1}{x ^{2}}

f (x) = 12 - x^{4}

What is the domain of y=sqrt(5(x-5)+40) ?
The domain of y=sqrt(5(x-5)+40) is x>=-3