What is the domain of p(x)=sqrt((x^2-4x-32)/(x-1)) ?

The domain of p(x)=sqrt((x^2-4x-32)/(x-1)) is -4 = 8

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domain of p(x)=sqrt((x^2-4x-32)/(x-1))

domain

p (x) = \frac{x ^{2} - 4 x - 32}{x - 1}

- 4 \leq x < 1 or x \geq 8

Interval Notation

[- 4, 1) \cup [8, \infty)

Solution steps

Find non-negative values for radicals:

- 4 \leq x < 1 or x \geq 8

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

- 4 \leq x < 1 or x \geq 8

\frac{9 ( x ^{2} - x - 56 )}{10 ( x ^{2} - 64 )}

f (x) = 2 \cdot x^{1} + 1.8 \cdot x^{2}

F (x) = ∣ 2 x + 1 ∣

g (x) = 3 + lo g_{3} (x + 2)

f (x) = 8 x (x - 2) (x - 9)

What is the domain of p(x)=sqrt((x^2-4x-32)/(x-1)) ?
The domain of p(x)=sqrt((x^2-4x-32)/(x-1)) is -4<= x<1\lor x>= 8