What is the domain of x/(\sqrt[3]{9x-6)} ?

The domain of x/(\sqrt[3]{9x-6)} is x 2/3

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domain of x/(\sqrt[3]{9x-6)}

domain

x < \frac{2}{3} or x > \frac{2}{3}

Interval Notation

(- \infty, \frac{2}{3}) \cup (\frac{2}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{2}{3}

The function domain

x < \frac{2}{3} or x > \frac{2}{3}

10 x^{4} - 27 x^{3} - 19 x^{2} + 42 x - 36

f (x) = 36 x^{2} + 84 x + 49

f (x) = 144 x - 2 x^{2}

\frac{x - 7}{6}

2 x^{2} + 6 x + 6

What is the domain of x/(\sqrt[3]{9x-6)} ?
The domain of x/(\sqrt[3]{9x-6)} is x< 2/3 \lor x> 2/3