What is the domain of (x^{1/2})/((x-3)) ?

The domain of (x^{1/2})/((x-3)) is 0 3

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domain of (x^{1/2})/((x-3))

domain

\frac{x ^{\frac{1}{2}}}{( x - 3 )}

0 \leq x < 3 or x > 3

Interval Notation

[0, 3) \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 3

Combine real regions and undefined points for final function domain

0 \leq x < 3 or x > 3

- 0.015 x^{2} + 1.22 x - 7.2

f (x) = ln (x^{2} - 8 x + 15)

f (x) = - 3 x + 1 - 4 x + 5

f (x) = \frac{3 x}{x - 7}

x^{5} - 5

What is the domain of (x^{1/2})/((x-3)) ?
The domain of (x^{1/2})/((x-3)) is 0<= x<3\lor x>3