What is the domain of f(x)=(\sqrt[3]{2+x})/(3-x) ?

The domain of f(x)=(\sqrt[3]{2+x})/(3-x) is x 3

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domain of f(x)=(\sqrt[3]{2+x})/(3-x)

domain

x < 3 or x > 3

Interval Notation

(- \infty, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3

The function domain

x < 3 or x > 3

5 - x + 6

f (x) = \frac{x + 8}{x ^{2} + 4}

\frac{x ^{2} - 1}{- x ^{2} + 5}

f (x) = \frac{x}{17 x - 4}

f (x) = [- 40140]

What is the domain of f(x)=(\sqrt[3]{2+x})/(3-x) ?
The domain of f(x)=(\sqrt[3]{2+x})/(3-x) is x<3\lor x>3