What is the domain of 8/(x^2+x-6)-7/(x^2-x-2) ?

The domain of 8/(x^2+x-6)-7/(x^2-x-2) is x 2

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domain of 8/(x^2+x-6)-7/(x^2-x-2)

domain

\frac{8}{x ^{2} + x - 6} - \frac{7}{x ^{2} - x - 2}

x < - 3 or - 3 < x < - 1 or - 1 < x < 2 or x > 2

Interval Notation

(- \infty, - 3) \cup (- 3, - 1) \cup (- 1, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 3, x = - 1

The function domain

x < - 3 or - 3 < x < - 1 or - 1 < x < 2 or x > 2

f (x) = \frac{x - 5}{( x ^{2} - 9 )}

y, y \leq 3 x

f (x) = x^{2} - 13 = 13 - x^{2}

f (x) = lo g_{10} (3 x) 2 - x - 20

f (x) = - 3 2 x + 3 - 1

What is the domain of 8/(x^2+x-6)-7/(x^2-x-2) ?
The domain of 8/(x^2+x-6)-7/(x^2-x-2) is x<-3\lor-3<x<-1\lor-1<x<2\lor x>2