What is the domain of g(x)=4x-1h(x)=sqrt(x-3) ?

The domain of g(x)=4x-1h(x)=sqrt(x-3) is x>= 3

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domain of g(x)=4x-1h(x)=sqrt(x-3)

domain

g (x) = 4 x - 1 h (x) = x - 3

x \geq 3

Interval Notation

[3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 3

The function domain

x \geq 3

g (x) = \frac{( x + 7 ) ^{2}}{6 x - 2}

\frac{ln ( x ^{2} )}{x ^{2} - 1}

f (x) = lo g_{10} (4 x + 3) - 2

f (x) = ln (x + 3) + ln (x - 3)

y = \frac{8}{3 ^{2}} (- ∣ x ∣ + 5)^{2} + 10

What is the domain of g(x)=4x-1h(x)=sqrt(x-3) ?
The domain of g(x)=4x-1h(x)=sqrt(x-3) is x>= 3