What is the domain of f(x)=((-5x^2))/(2x-1) ?

The domain of f(x)=((-5x^2))/(2x-1) is x 1/2

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domain of f(x)=((-5x^2))/(2x-1)

domain

f (x) = \frac{( - 5 x ^{2} )}{2 x - 1}

x < \frac{1}{2} or x > \frac{1}{2}

Interval Notation

(- \infty, \frac{1}{2}) \cup (\frac{1}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{1}{2}

The function domain

x < \frac{1}{2} or x > \frac{1}{2}

h (x) = 3 \cdot (- 12)

h (x) = ln (6 x - 3)

\frac{12 x ^{2} + 24}{3 x ^{2} - 4 x - 7}

f (x) = \frac{4 x}{x ^{2} + 2 x - 15}

3 x^{3} + 4 x^{2} - x - 4

What is the domain of f(x)=((-5x^2))/(2x-1) ?
The domain of f(x)=((-5x^2))/(2x-1) is x< 1/2 \lor x> 1/2