What is the domain of y+5=-sqrt(x+1) ?

The domain of y+5=-sqrt(x+1) is x>=-1

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domain of y+5=-sqrt(x+1)

domain

y + 5 = - x + 1

x \geq - 1

Interval Notation

[- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

The function domain

x \geq - 1

f (x) = - (\frac{1}{4})^{x} - 2

f (x) = - (\frac{1}{4})^{x} - 3

2^{(x + 8)} - 2

f (x) = x + 3 x + 6 - x - 6 \cdot 2 - 49

f (x) = \frac{1}{sin ( x ) x}