What is the domain of f(x)=2arctan(sqrt(1-x^2)) ?

The domain of f(x)=2arctan(sqrt(1-x^2)) is -1<= x<= 1

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domain of f(x)=2arctan(sqrt(1-x^2))

domain

f (x) = 2 arctan (1 - x^{2})

- 1 \leq x \leq 1

Interval Notation

[- 1, 1]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 1

The function domain

- 1 \leq x \leq 1

f (x) = (2 x - 3) + x - 5

f (x) = \frac{x - 1}{x + 2} - 2

f (x) = \frac{1}{2} x - 8

x (4 - 3 x)

0.8413

What is the domain of f(x)=2arctan(sqrt(1-x^2)) ?
The domain of f(x)=2arctan(sqrt(1-x^2)) is -1<= x<= 1