What is the domain of y=sqrt(x^2-3x-4) ?

The domain of y=sqrt(x^2-3x-4) is x = 4

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domain of y=sqrt(x^2-3x-4)

domain

y = x^{2} - 3 x - 4

x \leq - 1 or x \geq 4

Interval Notation

(- \infty, - 1] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 4

The function domain

x \leq - 1 or x \geq 4

y = 4 x - \frac{1}{5}

5 x + 5 x - 6

\frac{x - 6}{2 x - 5}

f (x) = \frac{3}{x} - 5

f (x) = \frac{( x ^{2} - 4 x - 12 )}{x ^{2} - 25}

What is the domain of y=sqrt(x^2-3x-4) ?
The domain of y=sqrt(x^2-3x-4) is x<=-1\lor x>= 4