What is the domain of (sqrt(x-2))/(x^2-16) ?

The domain of (sqrt(x-2))/(x^2-16) is 2 4

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domain of (sqrt(x-2))/(x^2-16)

domain

\frac{x - 2}{x ^{2} - 16}

2 \leq x < 4 or x > 4

Interval Notation

[2, 4) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 4, x = - 4

Combine real regions and undefined points for final function domain

2 \leq x < 4 or x > 4

3 6^{x + 10} - 60

f (x) = \frac{x ^{2}}{x ^{3} - 3} + 3

2 - 9 - t^{2}

f (x) = \frac{- 4}{- ( - \frac{8}{- 2 x - 6} ) + 4}

What is the domain of (sqrt(x-2))/(x^2-16) ?
The domain of (sqrt(x-2))/(x^2-16) is 2<= x<4\lor x>4