What is the domain of f(x)=(-7x^2+3x-5)/(x+1) ?

The domain of f(x)=(-7x^2+3x-5)/(x+1) is x -1

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domain of f(x)=(-7x^2+3x-5)/(x+1)

domain

f (x) = \frac{- 7 x ^{2} + 3 x - 5}{x + 1}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

\frac{1 - x}{x x + 2}

\frac{( x + 3 )}{x ^{2} + 4 x - 5}

f (x) = \frac{ln ( x ^{2} - 9 )}{x ^{2} - 16}

f (x) = 2 x^{3} + 4 x^{2} + 2

(x - 14)^{2}, x \leq 14

What is the domain of f(x)=(-7x^2+3x-5)/(x+1) ?
The domain of f(x)=(-7x^2+3x-5)/(x+1) is x<-1\lor x>-1