What is the domain of h(x)=(sqrt(5x-25))^{-2} ?

The domain of h(x)=(sqrt(5x-25))^{-2} is x>5

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domain of h(x)=(sqrt(5x-25))^{-2}

domain

h (x) = (5 x - 25)^{- 2}

x > 5

Interval Notation

(5, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 5

Find undefined (singularity) points:

x = 5

Combine real regions and undefined points for final function domain

x > 5

h (x) = \frac{1}{x - 9}

f (x) = \frac{1}{x ^{2 - 8 x + 16}}

\frac{x + 3}{2 x ^{2} + 2}

f (x) = \frac{x ^{2} - 4 x - 12}{x - 2}

\frac{\frac{x}{x ^{2} + 1}}{\frac{x}{x ^{4} - 1}}

What is the domain of h(x)=(sqrt(5x-25))^{-2} ?
The domain of h(x)=(sqrt(5x-25))^{-2} is x>5