What is the domain of f(x)=(sqrt(x-4))/(x^2-10) ?

The domain of f(x)=(sqrt(x-4))/(x^2-10) is x>= 4

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domain of f(x)=(sqrt(x-4))/(x^2-10)

domain

f (x) = \frac{x - 4}{x ^{2} - 10}

x \geq 4

Interval Notation

[4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 4

Find undefined (singularity) points:

x = 10, x = - 10

Combine real regions and undefined points for final function domain

x \geq 4

y = \frac{3 a x ^{2}}{( 1 + x ^{3} )}

- \frac{3}{2} x^{2} - 39.5 x

f (x) = \frac{4 x}{9 - x}

f (x) = 4 - 2 e^{x}

f (x) = \frac{x - 2}{x ^{2} + 4 x - 21}

What is the domain of f(x)=(sqrt(x-4))/(x^2-10) ?
The domain of f(x)=(sqrt(x-4))/(x^2-10) is x>= 4