What is the domain of (2x^2-9x+10)/(2x^2+7x+6) ?

The domain of (2x^2-9x+10)/(2x^2+7x+6) is x -3/2

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domain of (2x^2-9x+10)/(2x^2+7x+6)

domain

\frac{2 x ^{2} - 9 x + 10}{2 x ^{2} + 7 x + 6}

x < - 2 or - 2 < x < - \frac{3}{2} or x > - \frac{3}{2}

Interval Notation

(- \infty, - 2) \cup (- 2, - \frac{3}{2}) \cup (- \frac{3}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{3}{2}, x = - 2

The function domain

x < - 2 or - 2 < x < - \frac{3}{2} or x > - \frac{3}{2}

f (x) = 2 x - 20

9 - y^{2}

2 x^{2} - 4 x - 30

- 1 + \frac{2 x - 60}{x ^{2} + 2 x - 63}

sin (cos (π x))

What is the domain of (2x^2-9x+10)/(2x^2+7x+6) ?
The domain of (2x^2-9x+10)/(2x^2+7x+6) is x<-2\lor-2<x<-3/2 \lor x>-3/2