What is the domain of f(x)=(sqrt(x))/(3x+9) ?

The domain of f(x)=(sqrt(x))/(3x+9) is x>= 0

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domain of f(x)=(sqrt(x))/(3x+9)

domain

f (x) = \frac{x}{3 x + 9}

x \geq 0

Interval Notation

[0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = - 3

Combine real regions and undefined points for final function domain

x \geq 0

f (x) = x^{5} - 1

7 - e^{2 x}

y = 3 - ∣ x + 1 ∣

4 x^{2} - 4, x \geq 0

2 - \frac{10}{x ^{2}}

What is the domain of f(x)=(sqrt(x))/(3x+9) ?
The domain of f(x)=(sqrt(x))/(3x+9) is x>= 0