What is the domain of sqrt((x-2)/3)+1 ?

The domain of sqrt((x-2)/3)+1 is x>= 2

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domain of sqrt((x-2)/3)+1

domain

\frac{x - 2}{3} + 1

x \geq 2

Interval Notation

[2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

The function domain

x \geq 2

10 x + 52

f (x) = \frac{1}{x - 2 x}

f (x) = \frac{x ^{2} + 9 - x}{x}

f (x) = \frac{5 x + 8}{3 x - 5}

f (x) = \frac{4 x ^{2} - 9}{x ^{2} - 25}