What is the domain of (3x(x-9))/(6x^2-41x-7) ?

The domain of (3x(x-9))/(6x^2-41x-7) is x 7

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domain of (3x(x-9))/(6x^2-41x-7)

domain

\frac{3 x ( x - 9 )}{6 x ^{2} - 41 x - 7}

x < - \frac{1}{6} or - \frac{1}{6} < x < 7 or x > 7

Interval Notation

(- \infty, - \frac{1}{6}) \cup (- \frac{1}{6}, 7) \cup (7, \infty)

Solution steps

Find undefined (singularity) points:

x = 7, x = - \frac{1}{6}

The function domain

x < - \frac{1}{6} or - \frac{1}{6} < x < 7 or x > 7

\frac{x ^{2} + x}{8 x - 32}

\frac{6 x ^{2} + 19 x + 8}{x ^{4} - 98 x ^{2} + 2401}

\frac{9 x}{x ^{2} - 25}

\frac{2 x ^{2} + x - 28}{x ^{2} - 3 x - 28}

f (x) = 5 - 4 x, x < 2

What is the domain of (3x(x-9))/(6x^2-41x-7) ?
The domain of (3x(x-9))/(6x^2-41x-7) is x<-1/6 \lor-1/6 <x<7\lor x>7