What is the domain of f(x)=(3x^2+x-4)/(x-1) ?

The domain of f(x)=(3x^2+x-4)/(x-1) is x 1

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domain of f(x)=(3x^2+x-4)/(x-1)

domain

f (x) = \frac{3 x ^{2} + x - 4}{x - 1}

x < 1 or x > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1

The function domain

x < 1 or x > 1

f (x) = \frac{x ^{2} + 2}{x - 5}

\frac{x - 6}{x ^{2} - 9 x + 18}

h (x) = 8 - x

f (x) = \frac{( 3 - 2 x )}{x - 1}

f (x) = \frac{- 3 2 x}{25} - 2

What is the domain of f(x)=(3x^2+x-4)/(x-1) ?
The domain of f(x)=(3x^2+x-4)/(x-1) is x<1\lor x>1