What is the domain of f(x)=sqrt(3x+42) ?

The domain of f(x)=sqrt(3x+42) is x>=-14

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domain of f(x)=sqrt(3x+42)

domain

f (x) = 3 x + 42

x \geq - 14

Interval Notation

[- 14, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 14

The function domain

x \geq - 14

f (x) = 2 x^{3} - x^{2} - 8 x + 4

f (x) = 2^{x + 1} + 1

g (x) = \frac{x + 4}{x ^{2} - 25}

x^{2} - x - 8

f (x) = \frac{x}{x ^{2} - 2}

What is the domain of f(x)=sqrt(3x+42) ?
The domain of f(x)=sqrt(3x+42) is x>=-14