What is the domain of f(x)=((sqrt(x-2)))/((x^2-x)) ?

The domain of f(x)=((sqrt(x-2)))/((x^2-x)) is x>= 2

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domain of f(x)=((sqrt(x-2)))/((x^2-x))

domain

f (x) = \frac{( x - 2 )}{( x ^{2} - x )}

x \geq 2

Interval Notation

[2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 1, x = 0

Combine real regions and undefined points for final function domain

x \geq 2

1 + 2 x

f (x) = \frac{( 9 x - 4 )}{4 x + 8}

f (x) = 2^{x + 1} - 3

x^{\frac{1}{3}} (x - 4)

- 4 x + 10, x \neq = 3

What is the domain of f(x)=((sqrt(x-2)))/((x^2-x)) ?
The domain of f(x)=((sqrt(x-2)))/((x^2-x)) is x>= 2