What is the domain of g(x)=log_{3}(x+2)+1 ?

The domain of g(x)=log_{3}(x+2)+1 is x>-2

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domain of g(x)=log_{3}(x+2)+1

domain

g (x) = lo g_{3} (x + 2) + 1

x > - 2

Interval Notation

(- 2, \infty)

Solution steps

Find positive values for logs:

x > - 2

The function domain

x > - 2

y = \frac{1}{lo g _{10} ( ∣ x ∣ )}

x^{5} - 4 x^{3} + 4 x - 1

lo g_{10} (x - 1)

f (x) = - 2 x + 2 - 3

f (x) = x^{3} - 7 x^{2} + 6^{x}

What is the domain of g(x)=log_{3}(x+2)+1 ?
The domain of g(x)=log_{3}(x+2)+1 is x>-2