What is the domain of g(t)=sqrt(t^2)+4 ?

The domain of g(t)=sqrt(t^2)+4 is -infinity <t<infinity

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domain of g(t)=sqrt(t^2)+4

domain

g (t) = t^{2} + 4

- \infty < t < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < t < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < t < \infty

- 4 + 5 x^{2}

f (x) = (x - 3) + 2

f (x) = \frac{17 x - 16}{6 x + 4}

f (x) = \frac{2}{3} + 2

f (1) = \frac{ln ( χ )}{χ ^{2}}

What is the domain of g(t)=sqrt(t^2)+4 ?
The domain of g(t)=sqrt(t^2)+4 is -infinity <t<infinity