What is the domain of f(x)=sqrt((x+1)(2x+3)) ?

The domain of f(x)=sqrt((x+1)(2x+3)) is x =-1

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domain of f(x)=sqrt((x+1)(2x+3))

domain

f (x) = (x + 1) (2 x + 3)

x \leq - \frac{3}{2} or x \geq - 1

Interval Notation

(- \infty, - \frac{3}{2}] \cup [- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - \frac{3}{2} or x \geq - 1

The function domain

x \leq - \frac{3}{2} or x \geq - 1

f (x) = lo g_{10} (x^{2} - 9 x)

f (x) = 3 x - 2

f (x) = lo g_{2} (8 - 2 x - x^{2})

f (x) = ln (x + 1) - ln (3 - x)

f (x) = \frac{∣ x ∣}{∣ x ∣ + 1}

What is the domain of f(x)=sqrt((x+1)(2x+3)) ?
The domain of f(x)=sqrt((x+1)(2x+3)) is x<=-3/2 \lor x>=-1