What is the domain of sqrt(8x^2-48x) ?

The domain of sqrt(8x^2-48x) is x = 6

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domain of sqrt(8x^2-48x)

domain

8 x^{2} - 48 x

x \leq 0 or x \geq 6

Interval Notation

(- \infty, 0] \cup [6, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 6

The function domain

x \leq 0 or x \geq 6

\frac{- 1 - 1 - 20 x}{10}

f (x) = ln (8 x - 8)

f (x) = lo g_{10} (\frac{3 x}{( x - 2 )})

f (x) = 2.69 + 0.48 (x - 1)

3 x - 1 - 9 - x^{2}

What is the domain of sqrt(8x^2-48x) ?
The domain of sqrt(8x^2-48x) is x<= 0\lor x>= 6