What is the perpendicular 3x+4y=5,\at ((-2,4)/7) ?

The perpendicular 3x+4y=5,\at ((-2,4)/7) is y= 4/3 x+b

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perpendicular 3x+4y=5,\at ((-2,4)/7)

perpendicular

3 x + 4 y = 5, at (\frac{- 2 , 4}{7})

y = \frac{4}{3} x + b

Solution steps

Find the slope of

3 x + 4 y = 5 : m = - \frac{3}{4}

Compute the slope of the perpendicular line:

m_{p} = \frac{4}{3}

Line with slope m=

\frac{4}{3} : y = \frac{4}{3} x + b

y = \frac{4}{3} x + b

f (x) = x^{2} + 11

lo g_{4} (x^{3} + 2)

6 - \frac{1}{2} x

y = - 3 x + 1

h (x) = x^{2} + 2 x

What is the perpendicular 3x+4y=5,\at ((-2,4)/7) ?
The perpendicular 3x+4y=5,\at ((-2,4)/7) is y= 4/3 x+b