What is the domain of f(x)= 1/((\frac{x){x+1})} ?

The domain of f(x)= 1/((\frac{x){x+1})} is x 0

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domain of f(x)= 1/((\frac{x){x+1})}

domain

f (x) = \frac{1}{( \frac{x}{x + 1} )}

x < - 1 or - 1 < x < 0 or x > 0

Interval Notation

(- \infty, - 1) \cup (- 1, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 1

The function domain

x < - 1 or - 1 < x < 0 or x > 0

g (t) = 6 t^{4} - 8 t^{3} + 14

f (x) = - ∣ x + 2 ∣ + 3

f (x) = \frac{x - 5}{( x - 4 ) ( x - 3 )}

f (x) = ln (8 x - 1)

f (x) = x^{2} + y^{2} + z^{2} = 0

What is the domain of f(x)= 1/((\frac{x){x+1})} ?
The domain of f(x)= 1/((\frac{x){x+1})} is x<-1\lor-1<x<0\lor x>0