What is the domain of f(x)=(-2x^2+7)/(5x-8) ?

The domain of f(x)=(-2x^2+7)/(5x-8) is x 8/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(-2x^2+7)/(5x-8)

domain

f (x) = \frac{- 2 x ^{2} + 7}{5 x - 8}

x < \frac{8}{5} or x > \frac{8}{5}

Interval Notation

(- \infty, \frac{8}{5}) \cup (\frac{8}{5}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{8}{5}

The function domain

x < \frac{8}{5} or x > \frac{8}{5}

- 3 (x + 2)^{2} + 7

f (x) = 77 x^{\frac{16}{3}}

1 - 6 x

\frac{x + 4}{x}

What is the domain of f(x)=(-2x^2+7)/(5x-8) ?
The domain of f(x)=(-2x^2+7)/(5x-8) is x< 8/5 \lor x> 8/5