What is the domain of y=\sqrt[3]{x}+2 ?

The domain of y=\sqrt[3]{x}+2 is -infinity <x<infinity

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domain of y=\sqrt[3]{x}+2

domain

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

y = 3 t^{2} + \frac{6}{3 t ^{2}} - 4 t

y = \frac{x + 7}{4 - x ^{2} - 9}

f (x) = - 8 x + 8

f (x) = tan (x) + 3

y = arcsin (\frac{x}{2} + 5) + \frac{π}{8}

What is the domain of y=\sqrt[3]{x}+2 ?
The domain of y=\sqrt[3]{x}+2 is -infinity <x<infinity