What is the domain of (sqrt(16-x^2-4))/(2-|x-3|) ?

The domain of (sqrt(16-x^2-4))/(2-|x-3|) is -2sqrt(3)<= x<1\lor 1<x<= 2sqrt(3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of (sqrt(16-x^2-4))/(2-|x-3|)

domain

\frac{16 - x ^{2} - 4}{2 - ∣ x - 3 ∣}

- 23 \leq x < 1 or 1 < x \leq 23

Interval Notation

[- 23, 1) \cup (1, 23]

Solution steps

Find non-negative values for radicals:

- 23 \leq x \leq 23

Find undefined (singularity) points:

x = 1, x = 5

Combine real regions and undefined points for final function domain

- 23 \leq x < 1 or 1 < x \leq 23

\frac{7}{\frac{6}{x - 5}}

f (x) = \frac{8 x}{( x - 2 ) ( x - 7 )}

f (x) = \frac{3}{x ^{2} + 9} + \frac{1}{x ^{2} - 1}

3 x^{2} - 5 x + 2

What is the domain of (sqrt(16-x^2-4))/(2-|x-3|) ?
The domain of (sqrt(16-x^2-4))/(2-|x-3|) is -2sqrt(3)<= x<1\lor 1<x<= 2sqrt(3)