What is the domain of f(x)=\sqrt[3]{x-3}+7/5 ?

The domain of f(x)=\sqrt[3]{x-3}+7/5 is -infinity <x<infinity

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domain of f(x)=\sqrt[3]{x-3}+7/5

domain

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

y = \frac{6 t - t ^{3}}{7 - t - 4 t ^{2}}

f (x) = (- 2.3)

\frac{( \frac{1}{x ^{2}} - 3 )}{3 - x}

f (x) = \frac{x - 5}{3 x ^{2} - 12}

x - ln (x)

What is the domain of f(x)=\sqrt[3]{x-3}+7/5 ?
The domain of f(x)=\sqrt[3]{x-3}+7/5 is -infinity <x<infinity