What is the domain of f(x)=((2x))/((sqrt(x^2-3x+2))) ?

The domain of f(x)=((2x))/((sqrt(x^2-3x+2))) is x 2

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domain of f(x)=((2x))/((sqrt(x^2-3x+2)))

domain

f (x) = \frac{( 2 x )}{( x ^{2} - 3 x + 2 )}

x < 1 or x > 2

Interval Notation

(- \infty, 1) \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 1 or x \geq 2

Find undefined (singularity) points:

x = 2, x = 1

Combine real regions and undefined points for final function domain

x < 1 or x > 2

- \frac{1}{4} - 5

f (x) = 9 - 7 \cdot 10 - 2 x

\frac{arcsin ( \frac{x}{2} )}{6}

\frac{1}{3 - ( \frac{x}{x - 1} )}

f (x) = 12 x^{3} - 5 x^{2} 11 x + 6

What is the domain of f(x)=((2x))/((sqrt(x^2-3x+2))) ?
The domain of f(x)=((2x))/((sqrt(x^2-3x+2))) is x<1\lor x>2