What is the domain of f(x)= 1/(sqrt(5-2t)) ?

The domain of f(x)= 1/(sqrt(5-2t)) is t< 5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)= 1/(sqrt(5-2t))

domain

f (x) = \frac{1}{5 - 2 t}

t < \frac{5}{2}

Interval Notation

(- \infty, \frac{5}{2})

Solution steps

Find non-negative values for radicals:

t \leq \frac{5}{2}

Find undefined (singularity) points:

t = \frac{5}{2}

Combine real regions and undefined points for final function domain

t < \frac{5}{2}

2 e^{- x} arctan (x)

f (x) = - 2 x^{3}

e^{x^{3} - 6 x^{2} - 16 x} (3 x^{2} - 12 x - 16)

f (x) = \frac{4 x + 3}{x ^{3} - 2 x}

What is the domain of f(x)= 1/(sqrt(5-2t)) ?
The domain of f(x)= 1/(sqrt(5-2t)) is t< 5/2