What is the domain of f(x)= 1/(x^2+x-12) ?

The domain of f(x)= 1/(x^2+x-12) is x 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)= 1/(x^2+x-12)

domain

f (x) = \frac{1}{x ^{2} + x - 12}

x < - 4 or - 4 < x < 3 or x > 3

Interval Notation

(- \infty, - 4) \cup (- 4, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 4

The function domain

x < - 4 or - 4 < x < 3 or x > 3

f (x) = (- 2 x^{2} + 3) (x + 2)

f (x) = \frac{20}{x ^{2} - 4 x - 4}

\frac{x + 11}{x - 9}

9 t - 81

f (x) = [- 5.5]

What is the domain of f(x)= 1/(x^2+x-12) ?
The domain of f(x)= 1/(x^2+x-12) is x<-4\lor-4<x<3\lor x>3