What is the domain of 1/(\frac{5){-8x-10}+2} ?

The domain of 1/(\frac{5){-8x-10}+2} is x -15/16

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domain of 1/(\frac{5){-8x-10}+2}

domain

\frac{1}{\frac{5}{- 8 x - 10} + 2}

x < - \frac{5}{4} or - \frac{5}{4} < x < - \frac{15}{16} or x > - \frac{15}{16}

Interval Notation

(- \infty, - \frac{5}{4}) \cup (- \frac{5}{4}, - \frac{15}{16}) \cup (- \frac{15}{16}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{15}{16}, x = - \frac{5}{4}

The function domain

x < - \frac{5}{4} or - \frac{5}{4} < x < - \frac{15}{16} or x > - \frac{15}{16}

f (x) = \frac{x - 3}{x ^{2} - 2 x - 15}

\frac{2}{3} x^{3} + 2 x^{2} + 6 x - 5

f (x) = tan (2 x + 1)

g (x) = 3^{x} - 3

(x - 2) \cdot (3 x^{2} + 5 x)

What is the domain of 1/(\frac{5){-8x-10}+2} ?
The domain of 1/(\frac{5){-8x-10}+2} is x<-5/4 \lor-5/4 <x<-15/16 \lor x>-15/16