What is the domain of (sqrt(3x-5))/(2x+1) ?

The domain of (sqrt(3x-5))/(2x+1) is x>= 5/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of (sqrt(3x-5))/(2x+1)

domain

\frac{3 x - 5}{2 x + 1}

x \geq \frac{5}{3}

Interval Notation

[\frac{5}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{5}{3}

Find undefined (singularity) points:

x = - \frac{1}{2}

Combine real regions and undefined points for final function domain

x \geq \frac{5}{3}

8 x^{4} + 24 x^{2} + 21

f (x) = \frac{x + 1}{x + 2}

(\frac{y - 1}{2 y})^{2}

f (x) = (x + 2)^{\frac{1}{2}} + 3

\frac{3 x ^{2} - 3}{2 x ^{2}}

What is the domain of (sqrt(3x-5))/(2x+1) ?
The domain of (sqrt(3x-5))/(2x+1) is x>= 5/3