What is the domain of f(x)=(x^2+6x-7)/(x^2+2x-3) ?

The domain of f(x)=(x^2+6x-7)/(x^2+2x-3) is x 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(x^2+6x-7)/(x^2+2x-3)

domain

f (x) = \frac{x ^{2} + 6 x - 7}{x ^{2} + 2 x - 3}

x < - 3 or - 3 < x < 1 or x > 1

Interval Notation

(- \infty, - 3) \cup (- 3, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 3

The function domain

x < - 3 or - 3 < x < 1 or x > 1

f (x) = \frac{5 x + 2}{3 x ^{2} - 18 x + 27}

f (x) = \frac{1 - sin ( x )}{cos ( x )}

y = \frac{5}{3 x - 1}

f (x) = \frac{7 x}{5 x - 9}

\frac{( 8 x + 5 )}{4 x + 2}

What is the domain of f(x)=(x^2+6x-7)/(x^2+2x-3) ?
The domain of f(x)=(x^2+6x-7)/(x^2+2x-3) is x<-3\lor-3<x<1\lor x>1